(X^2-4x)/6-(5x)/3=1

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Solution for (X^2-4x)/6-(5x)/3=1 equation: 


x in (-oo:+oo)

(X^2-(4*x))/6-((5*x)/3) = 1 // - 1

(X^2-(4*x))/6-((5*x)/3)-1 = 0

(X^2-4*x)/6+(-5/3)*x-1 = 0

(X^2-4*x)/6+(-5*x)/3-1 = 0

(3*(X^2-4*x))/(3*6)+(-5*6*x)/(3*6)+(-1*3*6)/(3*6) = 0

3*(X^2-4*x)-5*6*x-1*3*6 = 0

3*X^2-42*x-18 = 0

(3*X^2-42*x-18)/(3*6) = 0

(3*X^2-42*x-18)/(3*6) = 0 // * 3*6

3*X^2-42*x-18 = 0

3*X^2-42*x-18 = 0 // - 3*X^2-18

-42*x = -(3*X^2-18) // : -42

x = (-(3*X^2-18))/(-42)

x = (18-(3*X^2))/(-42)

x = (18-(3*X^2))/(-42)

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